Function arrayOfAll

arrayOfAll<T>(): <U extends T[] | readonly T[]>(
array: U & ([T] extends [U[number]] ? unknown : "Invalid"),
) => U & ([T] extends [U[number]] ? unknown : "Invalid")
Ensure an array contains all desired values
Type Parameters
- T
Returns <U extends T[] | readonly T[]>(
array: U & ([T] extends [U[number]] ? unknown : "Invalid"),
) => U & ([T] extends [U[number]] ? unknown : "Invalid")
Borrows
SO comment by CertainPerformance
Usage
```
type Fruit = "pear" | "apple" | "orange";

const arrayOfAllFruits = arrayOfAll<Fruit>();

const allFruits = arrayOfAllFruits([ "pear", "apple", "orange" ]); // ts compiler ok
const allFruits = arrayOfAllFruits([ "pear", "apple" ]); // ts compiler fails
```
- Defined in arrayOfAll.ts:18